HTTP GET

suggest change

Python 2

import urllib
response = urllib.urlopen('http://stackoverflow.com/documentation/')

Using urllib.urlopen() will return a response object, which can be handled similar to a file.

print response.code
# Prints: 200

The response.code represents the http return value. 200 is OK, 404 is NotFound, etc.

print response.read()
'<!DOCTYPE html>\r\n<html>\r\n<head>\r\n\r\n<title>Documentation - Stack. etc'

response.read() and response.readlines() can be used to read the actual html file returned from the request. These methods operate similarly to file.read*

Python 3

import urllib.request

print(urllib.request.urlopen("http://stackoverflow.com/documentation/"))
# Prints: <http.client.HTTPResponse at 0x7f37a97e3b00>

response = urllib.request.urlopen("http://stackoverflow.com/documentation/")

print(response.code)
# Prints: 200
print(response.read())
# Prints: b'<!DOCTYPE html>\r\n<html>\r\n<head>\r\n\r\n<title>Documentation - Stack Overflow</title>

The module has been updated for Python 3.x, but use cases remain basically the same. urllib.request.urlopen will return a similar file-like object.

Feedback about page:

Feedback:
Optional: your email if you want me to get back to you:


urllib:
* HTTP GET

Table Of Contents
2 Filter
3 List
7 Loops
22 Reduce
27 Classes
31 Set
42 Tuple
45 Enum
62 Sockets
89 urllib
92 Idioms
104 Stack
105 Profiling
109 Logging
111 os module
118 Mixins
120 ArcPy
126 Arrays
132 2to3 tool
135 Unicode
138 Neo4j
140 Curses
141 Templates
145 heapq
146 tkinter
154 Audio
155 pyglet
157 ijson
160 Flask
161 Groupby
163 pygame
165 hashlib
166 Gzip
167 ctypes
185 pyaudio
186 shelve