Extracting zip file contents to a directory

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Extract all file contents of a zip file

import zipfile
with zipfile.ZipFile('zipfile.zip','r') as zfile:
    zfile.extractall('path')

If you want extract single files use extract method, it takes name list and path as input parameter

import zipfile
f=open('zipfile.zip','rb')
zfile=zipfile.ZipFile(f)
for cont in zfile.namelist():
    zfile.extract(cont,path)

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Working with ZIP files:
* Extracting zip file contents to a directory

Table Of Contents
2 Filter
3 List
7 Loops
22 Reduce
27 Classes
31 Set
42 Tuple
45 Enum
62 Sockets
89 urllib
92 Idioms
103 Working with ZIP files
104 Stack
105 Profiling
109 Logging
111 os module
118 Mixins
120 ArcPy
126 Arrays
132 2to3 tool
135 Unicode
138 Neo4j
140 Curses
141 Templates
145 heapq
146 tkinter
154 Audio
155 pyglet
157 ijson
160 Flask
161 Groupby
163 pygame
165 hashlib
166 Gzip
167 ctypes
185 pyaudio
186 shelve