One can give a function as many arguments as one wants, the only fixed rules are that each argument name must be unique and that optional arguments must be after the not-optional ones:
def func(value1, value2, optionalvalue=10):
return '{0} {1} {2}'.format(value1, value2, optionalvalue1)When calling the function you can either give each keyword without the name but then the order matters:
print(func(1, 'a', 100))
# Out: 1 a 100
print(func('abc', 14))
# abc 14 10Or combine giving the arguments with name and without. Then the ones with name must follow those without but the order of the ones with name doesn’t matter:
print(func('This', optionalvalue='StackOverflow Documentation', value2='is'))
# Out: This is StackOverflow Documentation