Essential Books

Accumulate names in a List

suggest change 
// Java:  
List<String> list = people.stream().map(Person::getName).collect(Collectors.toList());
// Kotlin:
val list = people.map { it.name }  // toList() not needed
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Java 8 Stream Equivalents:
* Java 8 Stream Equivalents
* Accumulate names in a List
* Collect example 5 - find people of legal age output formatted string
* Collect example 6 - group people by age print age and names together
* Counting items in a list after filter is applied
* Different Kinds of Streams 7 - lazily iterate Doubles map to Int map to String print each
* Different Kinds of Streams 3 - iterate a range of Integers
* Names of male members
* Group names of members in roster by gender
* Filter a list to another list
* Finding shortest string a list
* Different Kinds of Streams 2 - lazily using first item if exists
* Partition students into passing and failing
* Different Kinds of Streams 4 - iterate an array map the values calculate the average
* Different Kinds of Streams 5 - lazily iterate a list of strings map the values convert to Int find max
* Different Kinds of Streams 6 - lazily iterate a stream of Ints map the values print results
* Compute sum of salaries by department
* Group employees by department
* How streams work - filter upper case then sort a list
* Different Kinds of Streams 1 - eager using first item if it exists
* Compute sum of salaries of employee
* Convert elements to strings and concatenate them separated by commas
* Collect example 7a - Map names join together with delimiter
* Collect example 7b - Collect with SummarizingInt
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