Read XML using LINQ to XML

suggest change
<?xml version="1.0" encoding="utf-8" ?>
<Employees>
 <Employee>
  <EmpId>1</EmpId>
  <Name>Sam</Name>   
  <Sex>Male</Sex>
  <Phone Type="Home">423-555-0124</Phone>
  <Phone Type="Work">424-555-0545</Phone>
  <Address>
   <Street>7A Cox Street</Street>
   <City>Acampo</City>
   <State>CA</State>
   <Zip>95220</Zip>
   <Country>USA</Country>
  </Address>
</Employee>
<Employee>
 <EmpId>2</EmpId>
 <Name>Lucy</Name>
 <Sex>Female</Sex>
 <Phone Type="Home">143-555-0763</Phone>
 <Phone Type="Work">434-555-0567</Phone>
 <Address>
  <Street>Jess Bay</Street>
  <City>Alta</City>
  <State>CA</State>
  <Zip>95701</Zip>
  <Country>USA</Country>
  </Address>
 </Employee>
</Employees>

To read that XML file using LINQ

XDocument xdocument = XDocument.Load("Employees.xml");
IEnumerable<XElement> employees = xdocument.Root.Elements();
foreach (var employee in employees)
{
    Console.WriteLine(employee);
}

To access single element

XElement xelement = XElement.Load("Employees.xml");
IEnumerable<XElement> employees = xelement.Root.Elements();
Console.WriteLine("List of all Employee Names :");
foreach (var employee in employees)
{
    Console.WriteLine(employee.Element("Name").Value);
}

To access multiple elements

XElement xelement = XElement.Load("Employees.xml");
IEnumerable<XElement> employees = xelement.Root.Elements();
Console.WriteLine("List of all Employee Names along with their ID:");
foreach (var employee in employees)
{
    Console.WriteLine("{0} has Employee ID {1}",
    employee.Element("Name").Value,
    employee.Element("EmpId").Value);
}

To access all Elements having a specific attribute

XElement xelement = XElement.Load("Employees.xml");
var name = from nm in xelement.Root.Elements("Employee")
       where (string)nm.Element("Sex") == "Female"
       select nm;
Console.WriteLine("Details of Female Employees:");
foreach (XElement xEle in name)
Console.WriteLine(xEle);

To access specific element having a specific attribute

XElement xelement = XElement.Load("..\\..\\Employees.xml");
var homePhone = from phoneno in xelement.Root.Elements("Employee")
            where (string)phoneno.Element("Phone").Attribute("Type") == "Home"
            select phoneno;
Console.WriteLine("List HomePhone Nos.");
foreach (XElement xEle in homePhone)
{
    Console.WriteLine(xEle.Element("Phone").Value);
}

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LINQ to XML:
* Read XML using LINQ to XML

Table Of Contents
17 Regex
19 Arrays
21 Enum
22 Tuples
24 GUID
27 Looping
36 Casting
46 Methods
65 LINQ to XML
88 Events
92 Structs
104 Indexer
106 Stream
107 Timers
109 Threading
127 Caching
135 Pointers
147 C# Script