Collect all fields of JSON object

suggest change
using Newtonsoft.Json.Linq;
using System.Collections.Generic;

public class JsonFieldsCollector
{
    private readonly Dictionary<string, JValue> fields;

    public JsonFieldsCollector(JToken token)
    {
        fields = new Dictionary<string, JValue>();
        CollectFields(token);
    }

    private void CollectFields(JToken jToken)
    {
        switch (jToken.Type)
        {
            case JTokenType.Object:
                foreach (var child in jToken.Children<JProperty>())
                    CollectFields(child);
                break;
            case JTokenType.Array:
                foreach (var child in jToken.Children())
                    CollectFields(child);
                break;
            case JTokenType.Property:
                CollectFields(((JProperty) jToken).Value);
                break;
            default:
                fields.Add(jToken.Path, (JValue)jToken);
                break;
        }
    }

    public IEnumerable<KeyValuePair<string, JValue>> GetAllFields() => fields;
}

Usage:

var json = JToken.Parse(/* JSON string */);
var fieldsCollector = new JsonFieldsCollector(json);
var fields = fieldsCollector.GetAllFields();

foreach (var field in fields)
    Console.WriteLine($"{field.Key}: '{field.Value}'");

Demo For this JSON object

{
  "User": "John",
  "Workdays": {
    "Monday": true,
    "Tuesday": true,
    "Friday": false
  },
  "Age": 42
}

expected output will be:

User: 'John'
Workdays.Monday: 'True'
Workdays.Tuesday: 'True'
Workdays.Friday: 'False'
Age: '42'

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Using json.net:
* Collect all fields of JSON object

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