Essential Books

>> - right shift

suggest change 
#include <iostream>

int main(int argc, char **argv) {
    int a = 2;      // 0010b
    int b = a >> 1; // 0001b
    
    std::cout << "a = " << a << ", b = " << b << std::endl;
}
try online 
a = 2, b = 1

Why

The right bit wise shift will shift the bits of the left hand value (a) the number specified on the right (1); it should be noted that while the operation of a right shift is standard, what happens to the bits of a right shift on a signed negative number is implementation defined and thus cannot be guaranteed to be portable, example: 

int a = -2;    
int b = a >> 1; // the value of b will be depend on the compiler

It is also undefined if the number of bits you wish to shift by is a negative number, example: 

int a = 1;
int b = a >> -1;  // undefined behavior

The bit wise right shift does not change the value of the original values unless specifically assigned to using the bit wise assignment compound operator >>=: 

#include <iostream>

int main(int argc, char **argv) {
    int a = 2;  // 0010b
    a >>= 1;    // a = a >> 1;

    std::cout << "a = " << a  << std::endl;
}
try online 
a = 1
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Bit operators:
* | - bitwise OR
* ^ - bitwise XOR (exclusive OR)
* & - bitwise AND
* << - left shift
* >> - right shift
* ~ - bitwise NOT (unary complement)
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146 Contributors